CAN/ULC-S524 Clauses 3.3.1.3C, 5.14.2, and 5.14.6
Posted: Thu Mar 14, 2013 6:49
I am an electrician working for Vancouver Island Health Authority. At one of our hospitals, a new Simplex Grinnell addressable fire alarm system (with a 4100ES Panel) is being installed. Our DCL's are installed in style A with fault isolation modules.
Question 1: We have a hospital where there are a number of patient rooms that each have a separate bathroom accessable only from within the patient room. The patient room has a smoke detector and the bathroom a heat detector. The combined total of these rooms is much less than 100sq m. Clause 3.3.1.3 C of CAN/ULC-S524-06 allows a single conduit/raceway drop to pick up multiple field devices installed within a single room not exceeding 100sq m. Would this Clause allow a single conduit drop into the patient room to pick up the smoke detector and then a single conduit between bedroom smoke detector and bathroom heat detector if the combined total is less than 100sq m or do we have to treat bathroom and bedroom as separate rooms where a separate conduit drop would pick up the bedroom smoke detector and yet another separate drop would pick up the bathroom heat detector (as the Clause seems to imply)? Can we consider the sum total of bathroom and bedroom as a "single room" for the purposes of this rule if the sum total is less than 100sq m?
Question 2: In the same hospital, we have two rooms in a National Building Code of Canada required fire alarm zone that have a combined total area of much less than 100 sq m. As in Question 1, (with reference to our style A DCL) do we have to treat the two rooms as two separate single conduit drops to pick up a detector in each room or can we have a single conduit drop into this zone to pick up all detectors in both rooms?
Question 3: In the same hospital, we have a containment room with a single smoke detector. This room is less than 100 sq m. The style A DCL loop will pass by this room in another National Building Code of Canada required fire alarm zone. Clause 3.3.1.3 B or C of CAN/ULC-S524-06 allows a single conduit/raceway drop to pick up this smoke detector. Clause 5.14.2 requires isolation modules utilized when entering and leaving this containment room.
(a)Since we have both the primary wiring circuit and the alternate wiring circuit within a single conduit into this containment room from another zone, wouldn't Clause 5.14.2 require two isolation modules for the primary wiring circuit (one each on either side of the fire wall) and two isolation modules for the alternate wiring circuit (one each on either side of the fire wall) for a total of 4 isolation modules? Am I correct here?
(b)Clause 5.14.6 requires a minimum of 400mm of horizontal offset on either side of the firewall between the containment room and the other zone where the circuits are being fed from. What is a logical application of this rule? Would one leave a room with an isolation module, drill into the containment room and then immediately make a 90 degree bend and run the 400mm horizontal offset before installing the second isolation module? If 4 isolation modules are required in this situation, what physical spacial arrangement would satisfy Clause 5.14.6?
Thanks
Pat
Question 1: We have a hospital where there are a number of patient rooms that each have a separate bathroom accessable only from within the patient room. The patient room has a smoke detector and the bathroom a heat detector. The combined total of these rooms is much less than 100sq m. Clause 3.3.1.3 C of CAN/ULC-S524-06 allows a single conduit/raceway drop to pick up multiple field devices installed within a single room not exceeding 100sq m. Would this Clause allow a single conduit drop into the patient room to pick up the smoke detector and then a single conduit between bedroom smoke detector and bathroom heat detector if the combined total is less than 100sq m or do we have to treat bathroom and bedroom as separate rooms where a separate conduit drop would pick up the bedroom smoke detector and yet another separate drop would pick up the bathroom heat detector (as the Clause seems to imply)? Can we consider the sum total of bathroom and bedroom as a "single room" for the purposes of this rule if the sum total is less than 100sq m?
Question 2: In the same hospital, we have two rooms in a National Building Code of Canada required fire alarm zone that have a combined total area of much less than 100 sq m. As in Question 1, (with reference to our style A DCL) do we have to treat the two rooms as two separate single conduit drops to pick up a detector in each room or can we have a single conduit drop into this zone to pick up all detectors in both rooms?
Question 3: In the same hospital, we have a containment room with a single smoke detector. This room is less than 100 sq m. The style A DCL loop will pass by this room in another National Building Code of Canada required fire alarm zone. Clause 3.3.1.3 B or C of CAN/ULC-S524-06 allows a single conduit/raceway drop to pick up this smoke detector. Clause 5.14.2 requires isolation modules utilized when entering and leaving this containment room.
(a)Since we have both the primary wiring circuit and the alternate wiring circuit within a single conduit into this containment room from another zone, wouldn't Clause 5.14.2 require two isolation modules for the primary wiring circuit (one each on either side of the fire wall) and two isolation modules for the alternate wiring circuit (one each on either side of the fire wall) for a total of 4 isolation modules? Am I correct here?
(b)Clause 5.14.6 requires a minimum of 400mm of horizontal offset on either side of the firewall between the containment room and the other zone where the circuits are being fed from. What is a logical application of this rule? Would one leave a room with an isolation module, drill into the containment room and then immediately make a 90 degree bend and run the 400mm horizontal offset before installing the second isolation module? If 4 isolation modules are required in this situation, what physical spacial arrangement would satisfy Clause 5.14.6?
Thanks
Pat